00:01
Hi, today we are solving the question in which we need to evaluate firstly integral from 1 to 2 of 6x square minus 1 whole into dx.
00:11
Now here applying the sum rule and solving it.
00:15
So integral from 1 to 2 of 6x square into dx minus integral from 1 to 2 of 1 into dx.
00:26
Now solving it we get 6x cube by 3 and limits are from 1 to 2 minus x and limits are from 1 to 2.
00:45
Now 3, 1 and here it is 2.
00:48
So 2x cube will become here after putting the limits 14 minus 1.
00:55
So we get it as equals to 13.
00:57
So we can conclude that therefore required answer is equals to 13.
01:05
Now taking the second one we need to evaluate the integral from 0 to 1 of x raised to the power 5 minus 1 into x raised to the power 5 plus 1 whole into dx.
01:19
Now from here multiplying the conjugate.
01:24
So integral from 0 to 1 of x raised to the power 10 minus 1 divided by x raised to the power 5 plus 1 whole into x plus x raised to the power 5 plus 1 into dx.
01:37
Now simplifying and solving it.
01:40
So we get integral from 0 to 1 x raised to the power 10 minus 1 into dx.
01:47
On solving it we get integral from x raised to the power 10 minus 1 will become 11.
02:04
From here x raised to the power 11 by 11 plus not plus it is minus x and limits are from 0 to 1.
02:22
So from here on solving it we get it as minus 10 by 11.
02:29
So therefore required answer is minus 10 by 11.
02:38
Now similarly taking the next one.
02:41
So here we are given with integral from 1 to 2 of x square into under root x cube plus 8 whole into dx...