2. Find the matrix for the rotation of 60° with the center (2, 3, 1).
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Step 1: The matrix for a rotation of 60° about the origin is given by: $$ \begin{bmatrix} \cos 60^\circ & -\sin 60^\circ & 0 \\ \sin 60^\circ & \cos 60^\circ & 0 \\ 0 & 0 & 1 \end{bmatrix} = \begin{bmatrix} \frac{1}{2} & -\frac{\sqrt{3}}{2} & 0 Show more…
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