2. Find the vector equation of the line through the point (1, 1, 1) and perpendicular to the line \\ $l$ parametrized by r(t) = (2t + 1, 1, 3t - 1). \\ Recall: Two lines are perpendicular iff they intersect at a right angle.
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To find the direction vector of the given line, we need two points on the line. Since no other points are given, we can assume any point on the line. Let's assume the point (0, 0, 0) lies on the line. Then the direction vector of the line is given by the Show more…
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