Setting $y = \sqrt{x}$ and $y = x - 2$ equal to each other, we get $\sqrt{x} = x - 2$. Squaring both sides, we get $x = x^2 - 4x + 4$, which simplifies to $x^2 - 5x + 4 = 0$. Factoring, we get $(x - 1)(x - 4) = 0$, so $x = 1$ or $x = 4$. Since $y = \sqrt{x}$,
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