Question

2. For the reaction below, Kaolinite + 2Ca$^{2+}$ + 2H$_4$SiO$_4$ = 2 Anorthite + 10H$^+$ + H$_2$O calculate the equilibrium constant at 555K (282$^\circ$C) using the following data. $\Delta$H$^\circ$$_R$ (kcal/mol) $\Delta$G$^\circ$$_R$ (kcal/mol) Kaolinite -982.22 -905.61 Ca$^{2+}$ -129.7 -132.3 H$_4$SiO$_4$ -348.3 -312.6 Anorthite -1007.77 -954.3 H$^+$ 0 0 H$_2$O -68.32 -56.69

          2. For the reaction below,
Kaolinite + 2Ca$^{2+}$ + 2H$_4$SiO$_4$ = 2 Anorthite + 10H$^+$ + H$_2$O
calculate the equilibrium constant at 555K (282$^\circ$C) using the following data.
$\Delta$H$^\circ$$_R$ (kcal/mol)
$\Delta$G$^\circ$$_R$ (kcal/mol)
Kaolinite
-982.22
-905.61
Ca$^{2+}$
-129.7
-132.3
H$_4$SiO$_4$
-348.3
-312.6
Anorthite
-1007.77
-954.3
H$^+$
0
0
H$_2$O
-68.32
-56.69

2. For the reaction below,
Kaolinite + 2Ca^2+ + 2H4SiO4 = 2 Anorthite + 10H^+ + H2O
calculate the equilibrium constant at 555K (282^∘C) using the following data.
ΔH^∘R (kcal/mol)
ΔG^∘R (kcal/mol)
Kaolinite
-982.22
-905.61
Ca^2+
-129.7
-132.3
H4SiO4
-348.3
-312.6
Anorthite
-1007.77
-954.3
H^+
0
0
H2O
-68.32
-56.69

Added by Michael L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Jean Gephart

Step 1

Reaction: Kaolinite + 2Ca2+ + 2H4SiO4 = 2 Anorthite + 10H+ + H2O Reactants: Kaolinite, Ca2+, H4SiO4 Products: Anorthite, H+, H2O Show more…

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2. For the reaction below, Kaolinite + 2Ca2+ + 2H4SiO4 = 2 Anorthite + 10H+ + H2O calculate the equilibrium constant at 555K (282'C) using the following data. AHR (kcal/mol) GR (kcal/mol) Kaolinite Ca2+ H4SiO4 Anorthite H+ H2O 982.22 129.7 348.3 1007.77 0 68.32 905.61 132.3 312.6 954.3 0 56.69