2, Given 100.0 mL of a buffer that is 0.50 M in HOCl and 0.40 M in NaOCl. What is the pH after 10.0 mL of 1.0 M NaOH has been added? (Ka for HOCl = 3.5 x 10 -8) a. 7.55 b. 7.45 c. 6.45 d. 7.36 e. 6.64
Added by Anna B.
Step 1
First, we need to find the initial moles of HOCl and NaOCl in the buffer solution. Moles of HOCl = 0.50 M * 0.100 L = 0.050 moles Moles of NaOCl = 0.40 M * 0.100 L = 0.040 moles Show more…
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