Given 100.0 mL of a buffer that is 0.50 M in HOCl and 0.60 M in NaOCl, what is the pH after 10.0 mL of 1.0 M NaOH has been added? (Ka for HOCl = 3.5 x 10??) 7.46 7.63 7.70 7.21 7.55
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Given volume = 100.0 mL = 0.100 L Concentration of HOCl = 0.50 M Moles of HOCl = 0.100 L * 0.50 mol/L = 0.050 mol Show more…
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