2. In experiment 1, the illustration of the oxidation states of manganese, \( \mathrm{MnSO}_{4} \) was: used as one of the reactants for making Mn(III) from Mn(II). Use Slater's rules to predict and explain which of the two possibilities the more likely configuration for \( \mathrm{Mn}^{2 *} \) is: \( [\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d}^{3} \) or [Ar] \( 3 \mathrm{~d}^{5} \) ? 3. In valence bond theory, hypervalence is usually explained in terms of d-orbital participation in bonding. In the paper 'On the role of orbital hybridisation' ( J. Chem.
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In MnSO4, manganese is in the +2 oxidation state. This means that it has lost two electrons from its neutral state. Show more…
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