2 ? j4 ? a b -j2 ? 4 ? 60?0° V+ 6? 5?90° A -j3 ? 1) Find Zth...

2 ? j4 ? a b -j2 ? 4 ? 60?0° V+ 6? 5?90° A -j3 ? 1) Find $Z_{th}$ of Thevenin equivalent at terminals a-b. (3 point) 2) Find $V_{th}$ of Thevenin equivalent at terminals a-b. (5 point) 3) Find $I_N$, $Z_N$ of Norton equivalent at terminals a-b and draw the circuit. (2 point)

Transcript

00:01 Hello students, in this question given as the circuit now we have to find the equivalent circuit of the thevenin equivalent circuit of the circuit and the norton equivalent circuit.

00:10 So for the thevenin equivalent circuit we have to find the first of all thevenin voltage and then the thevenin resistance.

00:17 So for this we have to consider the thevenin voltage in this terminal a and b.

00:23 There will be the thevenin voltage and the current loop the first loop is this in which current i1 is flowing and second is the current loop is this in which the i2 current is flowing.

00:38 Now from the circuit we can see that the i1 current is equal to first i have to find the thevenin voltage.

00:50 The i1 current is equal to 2 ampere.

00:55 Next from the we have to apply the kirchhoff voltage law in loop 2, second loop.

01:06 So in this loop we can see that the minus 12 plus 4 ohm in bracket i2 minus i1 and plus 8 i2 and plus 8 i2 again and plus 5 i2 is equal to 0.

01:31 Now after putting the value of i1 is equal to 2 ampere in this equation we can find the i2 is equal to 0 .8 ampere 0 .8 ampere i1 and i2 we get.

01:48 So we can find the thevenin voltage is equal to 5 voltage is across the 5 ohm resistance and 5 ohm the current is flowing is i2 which is 0 .8.

02:01 So this will be equal to the 4 volt.

02:05 Thevenin voltage is equal to 4 volt.

02:08 Next we have to calculate the thevenin resistance.

02:13 The thevenin resistance for this we have to the current source we will the open circuit open circuit and the voltage source that means 12 volt we will the short circuit.

02:32 Now the circuit will looks like this.

02:37 Now the thevenin resistance will be equal to the 8, 4 and 8 ohm resistance is in series and this is parallel with the 5 ohm resistance.

02:50 So we can write 20 into 5 upon 20 plus 5.

02:56 So thevenin resistance will be equal to the 4 ohm.

03:03 Now the equivalent circuit of the thevenin equivalent circuit will looks like this...

Question

2 ? j4 ? a b -j2 ? 4 ? 60?0° V+ 6? 5?90° A -j3 ? 1) Find $Z_{th}$ of Thevenin equivalent at terminals a-b. (3 point) 2) Find $V_{th}$ of Thevenin equivalent at terminals a-b. (5 point) 3) Find $I_N$, $Z_N$ of Norton equivalent at terminals a-b and draw the circuit. (2 point)

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