Let A = 10, B = 11 and C = 12, D = 13. (a) Convert (AB6C7D)16 to decimal notation (base 10). (b) Convert (9A0B)16 to binary notation (base 2).
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(AB6C7D)16 = (10 * 16^5) + (11 * 16^4) + (6 * 16^3) + (12 * 16^2) + (7 * 16^1) + (13 * 16^0) = (10 * 1048576) + (11 * 65536) + (6 * 4096) + (12 * 256) + (7 * 16) + (13 * 1) = 10485760 + 720896 + 24576 + 3072 + 112 + 13 = 11223329 So, (AB6C7D)16 = 11223329 in Show more…
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