2. Let $F_i$ be the Fibonacci sequence. Prove by induction that (a) $\sum_{i=1}^{n} F_i = F_{n+2}$ (b) $\sum_{i=1}^{n} F_i^2 = F_n F_{n+1}$ (c) $F_n^2 - F_{n-1} F_{n+1} = (-1)^{n-1}$
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Step 1: **Base Case:** For n = 1, we have $F_1 = F_3 = 1$, which is true. Show more…
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(a) Show that the sum of the first n Fibonacci numbers with odd indices is given by the formula F1 + F3 + F5 + ... + F2n-1 = F2n [Hint: Add the equalities F1 = F2, F3 = F4 - F2, F5 = F6 - F4, ...] (b) Show that the sum of the first n Fibonacci numbers with even indices is given by the formula F2 + F4 + F6 + ... + F2n = F2n+1 - 1. [Hint: Use part a and the identity F1 + F2 + F3 + ... + F2n = F2n+2 - 1.] (c) Obtain the following formula for the alternating sum of Fibonacci numbers: F1 - F2 + F3 - F4 + ... + (-1)^(n+1) Fn = (-1)^(n+1) Fn-1 + 1.
Sri K.
$F_{n}$ denotes the $n$th term of the Fibonacci sequence discussed in Section $8.1 .$ Use mathematical induction to prove the statement. $$F_{1}+F_{3}+\dots+F_{2 n-1}=F_{2 n}$$
Sequences and Series
Mathematical Induction
Let f0, f1, f2, ..., fn, ... denote the Fibonacci sequence. By evaluating each of the following expressions for small values of n, conjecture a general formula and then prove it, using mathematical induction and the Fibonacci recurrence: (a) f1 + f3 + ... + f2n-1 (b) f0 + f2 + ... + f2n (c) f0 - f1 + f2 - ... + (-1)^n fn (d) f0^2 + f1^2 + ... + fn^2
Adi S.
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