Differentiate the Maclaurin series for \frac{1}{1 - 2x} twice to find the Maclaurin series of \frac{1}{(1 - 2x)^3}. Index the series so that the 0th term is nonzero.
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.. This can be written as: (1)/(1-2x) = Σ(2^n)(x^n) from n=0 to infinity Show more…
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