00:01
In this question part 2 we have our equation as limit x tends to 2 for x minus 2 divided by 4x squared minus 7x minus 2.
00:13
So first of all we have to factorize our denominator which is 4x square minus 7x minus 2.
00:20
So now for factorization we will use here middle term splitting method so our factors will be 8x minus 8x plus x minus 2.
00:30
So we will take common 4 in x, this will be x minus 2, and from the second two terms, we have one common, so x minus 2 again.
00:40
So we will have x minus 2, 4x plus 1.
00:44
So these are the factors of the denominator.
00:47
And now, as for the question, which we have limit x minus 2 further divided by 4x minus, i'm sorry, 4x plus 1, and x minus 2, and x minus 2.
01:03
2.
01:03
So we can see our 1 factor is canceling out and here x tends to so x tends to i'm sorry so on the next step we will get limit x tends to 2 1 upon 4x plus 1 and when we simplify as per putting our limit over here as here x is given as equal to 2 so x does not equal to 2 2 and so we can put here x minus 2 is equal to this does not equal to 0 and therefore it will be as 4 multiplied by 2 added by 1.
01:56
And now we will get here as 1 upon 9.
02:02
So here we have our answer for the second part of the question.
02:05
Answer for d1.
02:07
1 by 9 is the answer...