Question

2. Set up the integral for the area of the region bounded by the graphs of the equations. DO NOT EVALUATE THE INTEGRAL! $y = \frac{1}{2}x$ $y = x\sqrt{1-x^2}$

Name: 2 set up the integral for the area of the region bounded by the graphs of the equations do not evaluate the integral y frac12x y xsqrt1 x2 07626
Uploaded: 2022-09-15T17:24:53-08:00
Duration: 2 min 21 s
Channel: Gregory Higby
Description: 2 set up the integral for the area of the region bounded by the graphs of the equations do not evaluate the integral y frac12x y xsqrt1 x2 07626

          2. Set up the integral for the area of the region bounded by the graphs of the equations. DO NOT EVALUATE THE INTEGRAL!
$y = \frac{1}{2}x$
$y = x\sqrt{1-x^2}$

$2 set up the integral for the area of the region bounded by the graphs of the equations do not evaluate the integral y frac12x y xsqrt1 x2 07626$

Added by Jared J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Gregory Higby

09/15/2022

Step 1

$\frac{1}{2}x = x\sqrt{1-x^2}$ $\frac{1}{2} = \sqrt{1-x^2}$ (assuming $x \ne 0$) $\frac{1}{4} = 1 - x^2$ $x^2 = 1 - \frac{1}{4} = \frac{3}{4}$ $x = \pm\frac{\sqrt{3}}{2}$ Show more…

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2. Set up the integral for the area of the region bounded by the graphs of the equations. DO NOT EVALUATE THE INTEGRAL! $y = \frac{1}{2}x$ $y = x\sqrt{1-x^2}$