Question

2) Solve these equations by factorising. a) \( 5 x^{2}+6 x-11=0 \) (2) b) \( \quad(x+2)^{3}-3(x+2)^{2}=0 \) (2) \( \rightarrow \) Hint: DON'T do this by expanding! c) \( 2 \sqrt[3]{y}+2 \sqrt[6]{y}-12=0 \) [7 marks]

          2) Solve these equations by factorising.
a) \( 5 x^{2}+6 x-11=0 \)
(2)
b) \( \quad(x+2)^{3}-3(x+2)^{2}=0 \)
(2) \( \rightarrow \) Hint: DON'T do this by expanding!
c) \( 2 \sqrt[3]{y}+2 \sqrt[6]{y}-12=0 \)

[7 marks]

2) Solve these equations by factorising.
a) 5 x^2+6 x-11=0
(2)
b) (x+2)^3-3(x+2)^2=0
(2) → Hint: DON'T do this by expanding!
c) 2 √(y)+2 √(y)-12=0

[7 marks]

Added by John D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Piyush Kumar Gupta

03/14/2022

Step 1

1. Identify the quadratic equation: \(5x^2 + 6x - 11 = 0\). 2. Use the AC method: Multiply \(a\) and \(c\) (5 and -11) to get -55. 3. Find two numbers that multiply to -55 and add to 6. These numbers are 11 and -5. 4. Rewrite the middle term using these numbers: Show more…

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2) Solve these equations by factorising. a) \( 5 x^{2}+6 x-11=0 \) (2) b) \( \quad(x+2)^{3}-3(x+2)^{2}=0 \) (2) \( \rightarrow \) Hint: DON'T do this by expanding! c) \( 2 \sqrt[3]{y}+2 \sqrt[6]{y}-12=0 \) [7 marks]