\( 2 \tan \frac{x}{2}=\frac{\sin ^{2} x+1-\cos ^{2} x}{(\sin x)(1+\cos x)} \)
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The numerator is \(\sin^2 x + 1 - \cos^2 x\). Using the identity \(\sin^2 x + \cos^2 x = 1\), we can rewrite this as: \[ \sin^2 x + 1 - \cos^2 x = \sin^2 x + (1 - \cos^2 x) = \sin^2 x + \sin^2 x = 2\sin^2 x \] Show more…
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