2) The two blocks in the figure are connected by a heavy...

2) The two blocks in the figure are connected by a heavy uniform rope with a mass of 4.00 kg. An upward force of 200 N is applied as shown. (a) Draw three free-body diagrams: one for the 6.00-kg block, one for the 4.00-kg rope, and another one for the 5.00-kg block. For each force, indicate what body exerts that force. (b) What is the acceleration of the system? (c) What is the tension at the top of the heavy rope? (d) What is the tension at the midpoint of the rope? F = 200 N 6.00 kg 4.00 kg 5.00 kg

Transcript

00:01 So here we have the two blocks being connected with the string which is having the mass of 4kg and a force here as shown in the diagram here 200 newton is applied and first we need to draw the free body diagrams for all these three objects.

00:20 So if we see this object having mass 5kg here there is applied force of 200 newtons there will be tension here and there will be the weight and this weight will be its mass times acceleration due to gravity taking g as 10 weight will be 50 newtons talking about the free body diagram for this 4 kg string there will be tensions at the two ends and here there will be its weight also that will be in the downward direction so the weight will be also equal to m gs we do not need to determine that just we need to show all the forces and if we talk about the 7 kg object this also has the weight in the downward direction this has the tension in the upward direction now here we need to determine the acceleration of the system so to get the acceleration we use newton's second law that's the net force we divide it by the mass of the system so the net force is 200 and the total masses 5 plus 4 plus so that becomes 200 by 16 so if we simplify this we get the acceleration as 12 .5 meters per second so this gives us the acceleration as 12 .5 meters per second square and now we need to figure out the tension at the topmost point of the heavy rope so at the topmost point if we want to figure out the tension.

02:21 So we will see the free body diagram of this 5 kg object.

02:25 So there is the weight that's 50 newton's.

02:29 There is tension also in the downward direction and there is applied force of 200 newton's and because of this applied force, this block moves up with the acceleration which we have computed here.

02:43 So we use again newton's second law...

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