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2. What double precision floating point number is represented by the following 64-bit binary? Show your work. 0xC0557C00 00000000 3. What instruction at location 0x00400014 is represented by the following binary? Show your work: 0x110AFFFB

          2. What double precision floating point number is represented by the following 64-bit binary? Show your work.
0xC0557C00 00000000
3. What instruction at location 0x00400014 is represented by the following binary? Show your work:
0x110AFFFB
        
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2. What double precision floating point number is represented by the following 64-bit binary? Show your work.
0xC0557C00 00000000
3. What instruction at location 0x00400014 is represented by the following binary? Show your work:
0x110AFFFB

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Computer Science and Information Technology
Computer Science and Information Technology
Trishna Knowledge Systems 2018 Edition
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2. What double precision floating point number is represented by the following 64-bit binary? Show your work. 0C0557C00 00000000 3. What instruction at location 0x00400014 is represented by the following binary? Show your work OX11OAFFFB
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Transcript

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00:01 To perform a calculation using bcd arithmetic, first we convert the decimal number into bsd format.
00:07 First decimal number is 4314326.
00:13 Its bcd equivalent is 001, then 0100, 0011, 0010, and 0110.
00:27 Next number is 92378.
00:31 Its bcd arithmetic equivalent is 1001, 0010, 0011, 0111, again 1000.
00:47 Now we can add these bcd numbers and digits of bcd are a, b, c, d, f.
00:55 So the resultant number will be equal to 1010, 0110, 1001, and 1110.
01:08 Now since there are some invalid bcd digits, we can need to correct them by adding the 6 to those digits.
01:17 So we have been adding the 6 that is 0000, 0110, then again 0110, and 000.
01:33 So this will be equal to 1010, 1000, 1100, 1001, and 0100.
01:48 Now we have a valid bcd representation.
01:52 Converting it back to decimal, we get this is equal to 10674.
02:01 Therefore, 14326 plus 92378 is equal to 10674.
02:14 So the result of bcd addition is 10674.
02:22 Now next in part b, we need to represent 43 .125 in ieee 745754 floating point 8 -bit format and 4 -bit exponent.
02:37 We need to convert the binary numbers...
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