00:01
With this question, we are given this circuit diagram and we have a capacitor over here.
00:08
So we want to find electric parts in this question.
00:13
In part a, we want to find the electric fuel strength in the capacitor.
00:17
Then we need to find a displacement current in the capacitor.
00:22
And lastly, we need to find the b field at a point to our distance away from the from a point inside the capacitor.
00:32
So that diagram i would draw later.
00:35
Okay, so we are given a variable or time varying voltage.
00:41
So, and this is the function, okay, ut equals to 3t square minus 2t plus 3.
00:48
And in part a, we want to find the electric fuel strength inside the capacitor.
00:54
So we'll be using e equals to v over d or d, in this case is ut over d.
01:04
K, so and d is 0 .01 meters.
01:11
So e will just be 1 devout by 0 .0 .0 .01 times 3t square minus 2t plus 3.
01:22
Simplify you get 100 times 3t square minus 2 t plus 3.
01:29
And then at t equals to three seconds okay e will just be hundred times three times three square minus two times three plus three and you calculate this you get um twenty four hundred volts per meter okay so this is the answer for part a okay next you want to find the displacement current okay so in part b um be using a formula, okay, displacement current, okay, id is equal to f dot not, partial e, partial t, then times the area, s, okay.
02:28
So we have e equals to 100, 3t square minus 2t plus 3, that's from part a, so part e, part of t, just differentiate the above function respect to time, you get 100 times 6t minus 2.
02:47
Okay, and s is our area of the plate, which will be parr square.
02:55
Okay, so our id will be epsilon not times partial e, partial t, times the area...