20 2 points details my notes larcalcet7 41503xp 0100 submissions used find the absolute extrema

Name: 20 2 points details my notes larcalcet7 41503xp 0100 submissions used find the absolute extrema of the function on the closed interval fx x3 12x 0 6 minimum x y text maximum x y text 93158
Uploaded: 2023-09-06T21:02:10-08:00
Duration: 5 min 3 s
Channel: Adi S
Description: 20 2 points details my notes larcalcet7 41503xp 0100 submissions used find the absolute extrema of the function on the closed interval fx x3 12x 0 6 minimum x y text maximum x y text 93158

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Adi S · Accepted Answer

Step 1: Find the critical points of $f(x) = x^3 - 12x$ by taking the derivative and setting it t

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20. [-/2 Points] DETAILS MY NOTES LARCALCET7 4.1.503.XP. 0/100 Submissions Used Find the absolute extrema of the function on the closed interval. $f(x) = x^3 - 12x$, $[0, 6]$ minimum $(x, y) = (\text{______})$ maximum $(x, y) = (\text{______})$ Need Help? Read It

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20. [-/2 Points] DETAILS MY NOTES LARCALCET7 4.1.503.XP. 0/100 Submissions Used Find the absolute extrema of the function on the closed interval. $f(x) = x^3 - 12x$, $[0, 6]$ minimum $(x, y) = (\text{})$ maximum $(x, y) = (\text{})$ Need Help? Read It