00:01
Okay, we're going to look at the genotypes, phenotypes of a certain beetle population, which, you know, why not look at something a little different besides flies and mice? so we're told that there are two parents, and they're both true breeding, which is going to be important when we talk about genotypes.
00:18
So the first one has purple color and long antenna, and the second one has green color and short antenna.
00:30
And when these two are crossed to get our f1 generation, we have all purple beetles with long antenna.
00:40
And then we cross both of those to get the f2 generation.
00:44
And that information is listed, but we're going to use that in just a minute.
00:48
For now, i want to focus on what information we're given about genotypes based on just these first two generations.
00:57
So we see that in the parent generation, we have two different options at each.
01:02
Each locus.
01:05
And all of the f1 generation are purple and long.
01:11
They're all like that, which means that purple and long are both dominant traits.
01:20
So our dominant alleles are going to be attached to purple and long antenna.
01:24
Because the parents are true breeding, that means that the parent that is purple and has long antenna is homozygous dominant at both loci.
01:36
And thus the other parent that has the non -dominant traits, who is also true breeding, is homozygous recessive.
01:47
And so all of our f1 generation that have the dominant phenotype also got some recessive alleles from the other parent, meaning that there are complete heterozygotes.
01:59
So when we find our f2 generation, we are crossing two heterozygotes together.
02:06
This is important because in this question we want to know about the chai square test for the population, which requires us to have both observed ratios, which we are given and expected.
02:25
Meaning that for a moment, we got to find the expected ratios based on a die hybrid cross from the f1 generation with itself.
02:40
So to do this, we need a 4x4 square.
02:44
And then we're going to find all of the allelic combinations from the f1 generation, where we could have the first a with the first b, put it above the first column.
02:54
First a with the second b, next column.
02:58
Second a with the first b, next column.
03:02
Or the second a with the second b.
03:05
And you'll do that for the other f1 parent as well.
03:09
And since they are both heterozygotes, they actually have the same possible allot combinations.
03:16
Makes it easy...