00:01
The matrix given to us is a equals 3, minus 1, 1, minus 1, 4, 2, 1, 2, 5.
00:13
This is the matrix given to us and we have to solve for eigenvalues a minus lambda is equals to 0.
00:23
So, 3 minus lambda, minus 1, 1, minus 1, 4 minus lambda, 2, 1, 5 minus lambda equals 0.
00:41
So, therefore, my equation would become auxiliary equation minus 12 lambda to it plus 41 lambda minus 35 equals 0.
00:56
So, this is my auxiliary equation.
00:58
So, therefore, my eigenvalues are lambda equals to 1 .286, lambda 2 equals 4 .143 and lambda 3 equals 6 .571.
01:19
So, now let us find the eigenvectors.
01:25
So, eigenvector for lambda is lambda 1 equals 1 .286 equals.
01:33
So, this is basically 1 .714 minus 1, 1, minus 2 .714, 2, 1, 2, 3 .714 into x1, x2, x3, 0, 0, 0...