2018 Use the (delta -epsi lon) definition of a limit to show that lim_(x->2)(1-3x)=-5. 2018 Use the ( --e) definition of a limit to show that lim(1 -- 3) =- --.
Added by Christopher H.
Close
Step 1
Step 1: Start with the definition of a limit using the (\delta -\epsilon) definition: We want to show that for any \epsilon > 0, there exists a \delta > 0 such that if 0 < |x - 2| < \delta, then |(1-3x) - (-5)| < \epsilon. Show more…
Show all steps
Your feedback will help us improve your experience
Carson Merrill and 72 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the limit $L .$ Then use the $\varepsilon-\delta$ definition to prove that the limit is $L$. $$\lim _{x \rightarrow 3}|x-3|$$
Limits and Their Properties
Finding Limits Graphically and Numerically
Find the limit $L$. Then use the $\varepsilon-\delta$ definition to prove that the limit is $L$. $$ \lim _{x \rightarrow 2}(x+3) $$
Find the limit $L$. Then use the $\varepsilon-\delta$ definition to prove that the limit is $L$. $$ \lim _{x \rightarrow-3}\left(x^{2}+3 x\right) $$
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD