Jelani made a mistake solving an equation. His work is shown below. 5c - 3(2x + 4) = 2c - 4 Step 1: Distribute the -3 to the terms inside the parentheses. 5c - 6x - 12 = 2c - 4 Step 2: Combine like terms on both sides of the equation. 5c - 6x - 12 = 2c - 4 Step 3: Subtract 2c from both sides of the equation. 5c - 6x - 12 - 2c = -4 - 2c Step 4: Combine like terms on the left side of the equation. 5c - 2c - 6x - 12 = -4 - 2c Step 5: Subtract -2c from both sides of the equation. 5c - 2c - 6x - 12 + 2c = -4 - 2c + 2c Step 6: Combine like terms on the left side of the equation. 3c - 6x - 12 = -4 Step 7: Add 12 to both sides of the equation. 3c - 6x - 12 + 12 = -4 + 12 Step 8: Combine like terms on the left side of the equation. 3c - 6x = 8 Step 9: Divide both sides of the equation by 3. (3c - 6x)/3 = 8/3 Step 10: Simplify. c - 2x = 8/3
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In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a further step to isolate it. Let's say we now have: 3C + 4D = 5 2C + 5D = 2 None of these terms has a coefficient of 1. Instead, we'll pick the variable with the smallest coefficient and isolate it. Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. Now that you have one of the two variables in Part (A) isolated, use substitution to solve for the two variables. You may want to review the Multiplication and Division of Fractions and Simplifying an Expression Primers.
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