Consider the transformations f : R² → R² with f(x,y) = (x-3, y+2) and g : R² → R² with g(x,y) = (x+5, y-1). 1) Find the compositions f ∘ g and g ∘ f. 2) Find the inverses fâ»Â¹ and gâ»Â¹.
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So, if we start with (x,y) in R2, we have: f(g(x,y)) = f(c+5, y-1) = (c+2, y+1) Similarly, to find g 0 f, we need to apply f first and then g. So, if we start with (x,y) in R2, we have: g(f(x,y)) = g(x-3, y+2) = (x+2, y+1) 2) Show more…
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