Question

2.1 Simplify the following expression: \frac{20^{2n+1} \times 100^{2-n}}{64^{\frac{n}{3}}} 2.2 Solve for x: 2.2.1 $(log x)^2 - 5 = log(10x)$ 2.2.2 $3(x^2 + x^{-\frac{1}{2}}) = 10$

          2.1 Simplify the following expression:
\frac{20^{2n+1} \times 100^{2-n}}{64^{\frac{n}{3}}}
2.2 Solve for x:
2.2.1 $(log x)^2 - 5 = log(10x)$
2.2.2 $3(x^2 + x^{-\frac{1}{2}}) = 10$

2.1 Simplify the following expression:
(20^2n+1 ×100^2-n)/(64^(n)/(3))
2.2 Solve for x:
2.2.1 (log x)^2 - 5 = log(10x)
2.2.2 3(x^2 + x^-(1)/(2)) = 10

Added by Margaret B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Nick Johnson

02/06/2022

Step 1

Step 1: Simplify the expression 202n+1002-643 Combine like terms: 202n + 1002 - 643 = 202n + 359 Show more…

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2.1 Simplify the following expression: 202n+1002-643 2.2 Solve forx: 2.2.1 X 2.2.2 (logx-5=log10x 181 3x+x2=10

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Question

2.1 Simplify the following expression: \frac{20^{2n+1} \times 100^{2-n}}{64^{\frac{n}{3}}} 2.2 Solve for x: 2.2.1 $(log x)^2 - 5 = log(10x)$ 2.2.2 $3(x^2 + x^{-\frac{1}{2}}) = 10$

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