Using the quadratic formula, we have:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
In this case, a = 1, b = -6, and c = 1.
\[x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(1)(1)}}{2(1)}\]
Simplifying further:
\[x = \frac{6 \pm \sqrt{36 - 4}}{2}\]
\[x = \frac{6 \pm
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