00:01
Hi, in the question it is given that we have p1 is equal to 25 kn, we have p2 is equal to 60 kn, we have p3 is equal to 80 kn.
00:18
So let us understand the concept with the help of a diagram.
00:22
So here we have p1 and in this direction we have p2 and in this direction we have p3 and here we have 50 degree angle, here we have 40 degree angle and here we have theta and from here to here we have 4 meter and from here to here we have 6 meter.
00:45
So from this the forces must be concurrent from geometry.
01:10
So we will have h is equal to 4 plus b tan 40 degree which is equal to 6 minus b tan 50 degree.
01:29
So from here we will have 4 plus b and the value of tan 40 degree is 0 .839, approx will be equal to 6 minus b and the value of tan 50 degree is 1 .191.
01:53
So from here we will have 3 .356 plus 0 .839 b is equal to 7 .146 minus 1 .191 b.
02:13
So from here we will have 7 .146 minus 3 .356 will be equal to 0 .839 b plus 1 .191 b.
02:30
So we will have 3 .79 is equal to 2 .03 b.
02:36
So from here b will be equal to 3 .79 upon 2 .03 which is equal to 1 .8669 meter.
02:54
Therefore h will be equal to 4 plus 1 .8669 tan 40 degree.
03:05
So from here h will be equal to 5 .8669 multiplied by the value of tan 40 degree is 0 .839.
03:19
So from here h will be equal to 4 .924 meter.
03:26
Since we know that theta is equal to tan inverse of h, we can write theta as tan inverse of h...