00:01
In this question we are asked to find the total resistance of this circuit and power dissipated in this circuit.
00:09
So let's start to solve this problem.
00:11
Here these three registers are connected in parallel and let's say that the r1 is the equivalent resistance of this parallel combination.
00:20
So 1 over r1 is equal to 1 over 20k plus 1 over 60k plus 1 over 30 k is equal to 1 over 30 k is equal to 1 over is equal to 1 over 2 plus 1 over 6 plus 1 over 3 into 1 over 10 k.
00:39
Lcm is equal to 6, 3 plus 1 plus 2, 1 over 10 k, 3 plus 1 plus 2, 3 plus 1 4 plus 2 6 and 6 cancel out.
00:53
So from this we obtain r1 is equal to 10k.
01:00
Now this r1, this 4k and this 6k registers are connected in series.
01:08
And let's say that their series combination is equal to r2.
01:12
So r2 is given by r2 is equal to 6k plus 4k plus r1.
01:22
From this we obtain r2 is equal to 20k.
01:31
Now next we replace this branch by a 20 kilo -oom resistance...