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Hello everybody.
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The given circuit is ohmic circuit.
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Here 2 ohm resistance and 3 ohm resistance, they are in series connection.
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So their equivalent resistance r equivalent will be equal to 2 plus 3 ohm that is 5 ohm.
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Now this r equivalent and the 5 ohm resistance given in the circuit, they are in parallel.
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So their equivalent resistance r equivalent prime will be equal to r equivalent into 5 divided by r equivalent plus 5 and it will be 2 .5 ohm.
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Now this 2 .5 that is r equivalent prime ohm resistance will be in series with the 2 .5 ohm given in the circuit.
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So the final equivalent resistance r double prime equivalent will be r equivalent prime plus 2 .5 that will be total 5 ohm.
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So this is the equivalent resistance of the circuit.
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Now vg is given as 10 volt.
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So ix will be equal to vg divided by r double prime equivalent.
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So it will be 10 divided by 5 that is equal to 2 ampere...