2.26 [10] <§2.7> Translate the following C code to LEGv8...

2.26 [10] <§2.7> Translate the following C code to LEGv8 assembly code. Use a minimum number of instructions. Assume that the values of a, b, i, and j are in registers X0, X1, X10, and X11, respectively. Also, assume that register X2 holds the base address of the array D. for(i=0; i<a; i++) for(j=0; j<b; j++) D[4*j] = i + j;

Transcript

00:01 In this question, we have to write a assembly code that will translate the provided code to us, that is a code snippet into the leg p8, this assembly code.

00:19 So let us have a look at it.

00:21 So what we have to see here is that we have to write certain instructions and they will be meaning something.

00:29 So first we have to write the instructions that will load the value into the memory.

00:35 So we'll have instructions that will load the value into memory.

00:45 Then we are going to have something that will initialize the loop counter.

00:53 So we are looking at the steps that we have to write the code about.

01:00 Then what we can have is we have to have the beginning of the outer loop.

01:07 So for that, we will be having a certain loop i kind of code.

01:15 So we'll have the beginning of outer loop.

01:25 So then we will have the branches of the label that have greater than or equal to value.

01:33 And again, we will be having the comparison values ahead.

01:39 So let us have a look at a code in the basic compiler.

01:45 So we'll just look at any basic compiler as this is a assembly code.

01:51 So the first thing that we will be doing is we will be loading the d0 value into x3.

02:01 So now if you see we have loaded the value into x3 and then we have initialized the counter to 0.

02:10 Now the next thing that we will be doing is we will be looping i.

02:15 So in loop i, if we see we compare i with x0 and we compare i with respect to a and then we exit the outer loop.

02:30 Now we'll see the inner loop that is the loop j and its settings.

02:36 So now if we have a look over here, we have to compare a certain j with b and then we have to calculate the address of it.

02:46 So on proceeding over here, we can use this x5 for further processing if it is needed.

02:54 So we are using commands as calculate address of this and we have to store it in x4.

03:00 Then we have to load that value into x5.

03:03 So finally we get it in x5.

03:06 And then we increment j over here that is x11 and then we repeat the inner loop again.

03:16 Now we have to end j.

03:18 So for that we'll increment i and we'll have this repeat the outer loop step that is loop i.

03:28 Now after this, a code will end and we'll have a loop that gives a different value...

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