Question

2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities: (a) $U(\theta) = \cos \theta$ (b) $U(\theta) = \cos^2 \theta$ (c) $U(\theta) = \cos(2\theta)$ (d) $U(\theta) = \cos^2(2\theta)$ (e) $U(\theta) = \cos(3\theta)$ (f) $U(\theta) = \cos^2(3\theta)$ ($0 \le \theta \le 90^\circ, 0 \le \phi \le 360^\circ$)

Name: 24 find the half power beamwidth hpbw and first null beamwidth fnbw in radians and degrees for the following normalized radiation intensities a utheta cos theta b utheta cos2 theta c utheta 19019
Uploaded: 2024-05-20T08:06:22-08:00
Duration: 4 min 34 s
Channel: Adi S
Description: 24 find the half power beamwidth hpbw and first null beamwidth fnbw in radians and degrees for the following normalized radiation intensities a utheta cos theta b utheta cos2 theta c utheta 19019

          2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities:
(a) $U(\theta) = \cos \theta$
(b) $U(\theta) = \cos^2 \theta$
(c) $U(\theta) = \cos(2\theta)$
(d) $U(\theta) = \cos^2(2\theta)$
(e) $U(\theta) = \cos(3\theta)$
(f) $U(\theta) = \cos^2(3\theta)$
($0 \le \theta \le 90^\circ, 0 \le \phi \le 360^\circ$)

24 find the half power beamwidth hpbw and first null beamwidth fnbw in radians and degrees for the following normalized radiation intensities a utheta cos theta b utheta cos2 theta c utheta 19019

Added by Brian W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/20/2024

Step 1

The range for $\theta$ is $0 \le \theta \le 90^\circ$. The half-power beamwidth (HPBW) is the angular width between the two points where the radiation intensity is half of its maximum value. Since the radiation intensities are normalized, the maximum value is 1. Show more…

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2.4. Find the half-power beamwidth (HPBW) and first-null beamwidth (FNBW), in radians and degrees, for the following normalized radiation intensities: (a) $U(\theta) = \cos \theta$ (b) $U(\theta) = \cos^2 \theta$ (c) $U(\theta) = \cos(2\theta)$ (d) $U(\theta) = \cos^2(2\theta)$ (e) $U(\theta) = \cos(3\theta)$ (f) $U(\theta) = \cos^2(3\theta)$ ($0 \le \theta \le 90^\circ, 0 \le \phi \le 360^\circ$)