00:01
In this question we're given from a survey, 70 % of us adults aged 50 to 64 use the internet.
00:08
80 adults in this age group are randomly selected.
00:12
I'm going to let x be the number of adults out of the 80 in this sample who use the internet.
00:17
Now n, the number of trials, would be 80 since there are 80 adults.
00:21
In each trial we take a look at the adult in this sample and see whether he or she use the internet or not.
00:25
So all these 80 trials are identical and independent and we have p probability of success in a single trial, that's probability an adult in this age group use the internet and that'll be 70 % or 0 .7 decimal.
00:41
And this remains constant for all the trials.
00:44
So x follows the binomial distribution, n is 80, p is 0 .7.
00:53
But n is 80 is greater than 50, n times p, 80 times 0 .7, we'll get 56 which is greater than 5.
01:05
And we have n times 1 minus p and that will be 24 which is greater than 5.
01:14
Now these three criterias here shows that we, x actually can follow the normal distribution approximately with the mean as np which is 56 and the variance will be np times 1 minus p and that would be 16 .8.
01:39
Now because x was originally binomial which is discrete and now it follows normal distribution which is continuous, we have to use continuity correction.
01:50
In part a, we want to find probability at least 70 people say they use the internet.
01:55
So we're looking at probability of x greater equals to 70.
02:00
So by using continuity correction, i'll call it cc, we will be using this one here that is probability x greater than 70 minus 0 .5.
02:15
And so we're looking at probability of x greater than 69 .5.
02:19
Let's draw the distribution for x.
02:24
The mean is 56, 69 .5 is over here and x greater than that is this shaded area we're talking about.
02:32
I'll be using the ti -84 calculator, the normal cdf function.
02:40
Now to key in a lower limit and there'll be 69 .5.
02:45
Key in upper limit and there'll be a large positive number.
02:50
So usually i'll key in 10 to the power 99.
02:53
Mu is the mean of x and that's 56.
02:56
Sigma is the standard deviation of x and that will be the square root of the variance which is 16 .8.
03:04
And click enter, you'll get this value, four decimal place...