00:01
In this question we have a beam as shown in the figure.
00:04
A uniformly distributed load and uniformly varying load is acting on this beam as shown in the figure.
00:11
We are required to draw the three body diagram corresponding to this beam showing the force reaction in the pin support b and roller support at a.
00:22
After that we need to find the value of those reactions and finally we are required to calculate the resultant vertical force acting on the on this beam.
00:35
So let's see how to solve this question.
00:38
The free body diagram corresponding to this beam is shown below.
00:42
So this is the free body diagram corresponding to above beam.
00:46
Let's say the reaction at point a is ra reaction at point b is rb and since at point b there is a pin support therefore here we also have a horizontal reaction and let's say this is equals to hb.
01:11
This distance is 3 meter and this distance is 3 meter and here we have the loading 900 newton per meter and this uniform distributed load is 600 newton per meter so this is the final answer for part a and now let's move to part b to find the reactions first of all, let's equate the vertical forces so we can write summation f y is equal to 0.
01:55
So we will have reaction at a, ra plus rb is equal to 600 into 6 plus 1 upon 2 into 3 into 300.
02:13
When we further calculate we get ra plus rb is equal to 4 ,050 newtons and let's say this is equation 1.
02:26
Now let's take the moment about point a so we can write summation ma is equal to 0.
02:36
So we will have 6 into rb is equal to 600 into 6x into 6.
02:46
3 plus 1 upon 2 into 3 into 300 into 1 upon 3 into 3...