Question

25.7 mL of 0.095 M cyanic acid (HCNO) needed to be titrated with 0.17 M NaOH. The Ka for HCNO is 3.5 x 10–4 a) What is the initial pH of the acid solution? pH of the solution is Answer b) Calculate the volume (in mL) of NaOH solution will be needed to fully titrate the acid Volume of NaOH needed: Answer mL c) Determine the pH of the solution at the equivalence point. pH of the solution at the equivalence point is Answer d) Determine the pH of the solution if student A used 11.2 mL of 0.17 M NaOH solution to titrate the acid pH of the solution is Answer e) Determine the pH of the solution if student A used 21.9 mL of 0.17 M NaOH solution to titrate the acid pH of the solution is Answer

          25.7 mL of 0.095 M cyanic acid (HCNO) needed to be titrated with 0.17 M NaOH. The Ka for HCNO is 3.5 x 10–4
a) What is the initial pH of the acid solution?
pH of the solution is Answer
b) Calculate the volume (in mL) of NaOH solution will be needed to fully titrate the acid
Volume of NaOH needed: Answer
mL
c) Determine the pH of the solution at the equivalence point.
pH of the solution at the equivalence point is Answer
d) Determine the pH of the solution if student A used 11.2 mL of 0.17 M NaOH solution to titrate the acid
pH of the solution is Answer
e) Determine the pH of the solution if student A used  21.9 mL of 0.17 M NaOH solution to titrate the acid
pH of the solution is Answer

Added by Corey W.

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