27. In Fig. 16.22, BE is parallel to \( \mathrm{CD}, \mathrm{BA}=\mathrm{BC}, \angle \mathrm{ABE}=20^{\circ} \) and \( \angle \mathrm{DCG}=60^{\circ} \). Determine AA
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This means that angle BAC = angle BCA. Show more…
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#13) In the figure shown below, AC ≅ CE, BD ≅ BE, and AE ≅ DE. If Angle AED = 105°, calculate the measures of Angle AEC and Angle CAB. Color-code all corresponding congruent parts with the same color. Label congruent angles using letters such as x° and y°, etc. Use an equation about 105° to help you solve this problem. What geometry concepts are prerequisite knowledge? List at least 3. One is very important and I will be looking for it to give you credit. Angle AEC = Angle CAB =
Jeremiah M.
$$\begin{array}{c} \text { Given: } \overline{\mathrm{BE}} \approx \overline{\mathrm{BD}} \\ \overline{\mathrm{BE}} \perp \overline{\mathrm{AE}} \\ \angle \mathrm{BDC}=90^{\circ} \\ \text { Prove: } \angle \mathrm{AED} \equiv \angle \mathrm{CDE} \end{array}$$ (GRAPH CAN'T COPY)
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$\begin{aligned} \text { Given: } & \overline{\mathrm{CB}} \perp \overline{\mathrm{AB}} \\ & \dot{\mathrm{DE}} \end{aligned}$ $\angle \mathrm{CDE}=40^{\circ}$ Find: $\mathrm{m} \angle \mathrm{A}, \mathrm{m} \angle \mathrm{C},$ and $\mathrm{m} \angle \mathrm{CED}$ GRAPH CAN'T COPY.
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