Question

2. A shaft is made of solid round bar 30 mm diameter and 0.5 m long. The shear stress must not exceed 200 MPa. Calculate the following. i. The maximum torque that should be transmitted. ii. The angle of twist which will occur. Take G = 90 GPa. (Ans. 1060 Nm and 4.2°)

          2. A shaft is made of solid round bar 30 mm diameter and 0.5 m long. The shear stress must not exceed 200 MPa. Calculate the following.
i. The maximum torque that should be transmitted.
ii. The angle of twist which will occur.
Take G = 90 GPa.
(Ans. 1060 Nm and 4.2°)

2. A shaft is made of solid round bar 30 mm diameter and 0.5 m long. The shear stress must not exceed 200 MPa. Calculate the following.
i. The maximum torque that should be transmitted.
ii. The angle of twist which will occur.
Take G = 90 GPa.
(Ans. 1060 Nm and 4.2°)

Added by Ashley T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhat Tyagi

05/23/2025

Step 1

The maximum torque that should be transmitted: The formula for shear stress (τ) is τ = T*r/J, where T is the torque, r is the radius of the shaft, and J is the polar moment of inertia. The polar moment of inertia for a solid round shaft is J = π*(d^4)/32, where d Show more…

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A shaft is made of solid round bar with a diameter of 30 mm and a length of 0.5 m. The shear stress must not exceed 200 MPa. Calculate the following: 1. The maximum torque that should be transmitted. 2. The angle of twist which will occur. Take G = 90 GPa. Answer: 1,060 Nm and 4.20