We are given two probabilities related to the mean \(\bar{X}_{9}\) and the variance \(S_{9}\) of a sample of size 9:
- \(P(-0.3<\bar{X}_{9}<0.3) = 0.63\), which tells us the probability that the sample mean is between -0.3 and 0.3.
- \(P(0.9<S_{9}<1.1) = 0.15\),
Show more…