The diameter of the rod is 25 mm. The cross-sectional area \( A \) can be calculated using the formula for the area of a circle:
\[ A = \pi \left(\frac{d}{2}\right)^2 \]
\[ A = \pi \left(\frac{25 \text{ mm}}{2}\right)^2 \]
\[ A = \pi \left(12.5 \text{ mm}\right)^2
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