Question

2y = 2x + 29 is a tangent to the quadratic x^(2) - 2ky + 32k = 0, where k is a non-zero constant. Find the value of k and determine where the quadratic crosses the y-axis.

Name: 2y 2x 29 is a tangent to the quadratic x2 2ky 32k 0 where k is a non zero constant find the value of k and determine where the quadratic crosses the y axis 51923
Uploaded: 2024-10-28T20:13:34-08:00
Duration: 2 min 12 s
Channel: Hoan Nguyen
Description: 2y 2x 29 is a tangent to the quadratic x2 2ky 32k 0 where k is a non zero constant find the value of k and determine where the quadratic crosses the y axis 51923

          2y = 2x + 29 is a tangent to the quadratic x^(2) - 2ky + 32k = 0, where k is a non-zero constant. Find the value of k and determine where the quadratic crosses the y-axis.

Added by Kevin H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Hoan Nguyen

10/28/2024

Step 1

Divide the entire equation by 2 to get: \[ y = x + \frac{29}{2} \] Here, the slope \(m = 1\) and the y-intercept \(c = \frac{29}{2}\). Show more…

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2y = 2x + 29 is a tangent to the quadratic x^(2) - 2ky + 32k = 0, where k is a non-zero constant. Find the value of k and determine where the quadratic crosses the y-axis.