What is the concentration of W2B at equilibrium if the initial concentrations of W3 and B2 are 0.83 M and 0.46 M, respectively? The equilibrium constant is 3.9x10^11. The units of your answer should be molar, but not put into the answer. Only put the number into the answer box. If you want to use scientific notation, make sure you know how to do it in moodle. 2 W3(g) + 3 B2(g) ? 2 W3B3(g) Answer:
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The given reaction is: \[ \rm{2W(g) + 3B(g) \rightleftharpoons W_2B_3(g)} \] The equilibrium constant \( K \) for this reaction is given by: \[ K = \frac{[W_2B_3]}{[W]^2[B]^3} \] Given \( K = 3.9 \times 10^{11} \). Show more…
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