00:03
Hello students, in this question the displacement x is given as t minus 2 the whole cube minus t square plus 2.
00:15
So in the a part we have to find out the time at which the displacement is 0.
00:20
So x can be written as if you open the bracket we will get x will be equal to t cube minus 7 t square minus 6 plus 12 t.
00:31
So when displacement or the particle is at rest velocity v will be equal to 0 that is dx by dt will be equal to 0.
00:44
So this will be d by dt of t cube minus 7 t square minus 6 plus 12 t.
00:56
So if we differentiate we will get the velocity will be 3 t cube minus 14 t square plus 12 will be equal to 0.
01:06
So we can give this is equation number 1.
01:08
So this is a quadratic equation.
01:10
If we solve this equation we will get time t when the particle at rest will be 0 .76 seconds.
01:19
So in the b part we have to find out the displacement of the particle.
01:24
So we have to find out the displacement of the particle from time t equal to 0 seconds to 4 seconds...