00:01
In the given question we are told that a square loop of a wire upside 0 .2 meter, l is given .20 meter has a total resistance are 0 .60 oam.
00:14
The loop is positioned in uniform magnetic field b, that is 0 .030 tesla.
00:23
Here we have to calculate the magnetic flux through the loop.
00:26
So, to calculate magnetic flux, phi equals to b into a, that is 0 .03, area is square of the length, 0 .2 square.
00:42
So, 5 will be 1 .2 into 10 .2 minus 3 weber.
00:47
Now, we are told that b is increased to the final will be 0 .2 tesla in 0 .5 seconds.
01:00
So now we have to find induced emf e that is equals to n del phi by t which is a this will be b final minus initial divide by t we have all the values 0 .2 square 0 .2 minus 0 .03 divide by time that is 0 .5 so 0 .014 volt is 0 .0 .0 .0 .0 .0 .0 .0 .4 volt is 0 .4 volt is 0 .0 .0 .4 volt is 0...