Question

3. An aluminum conductor is 1000 ft. long and has a circular cross section with a diameter of 0.8 in². If there is a dc voltage of 1.2 V between the ends, find: (? = 3.82 x 10? mho/m²) a. the current density (5 pts) b. the current (5 pts) c. the power dissipated. (5 pts)

          3. An aluminum conductor is 1000 ft. long and has a circular cross section with a diameter of 0.8 in². If there is a dc voltage of 1.2 V between the ends, find: (? = 3.82 x 10? mho/m²)
a. the current density (5 pts)
b. the current (5 pts)
c. the power dissipated. (5 pts)

3. An aluminum conductor is 1000 ft. long and has a circular cross section with a diameter of 0.8 in². If there is a dc voltage of 1.2 V between the ends, find: (? = 3.82 x 10? mho/m²)
a. the current density (5 pts)
b. the current (5 pts)
c. the power dissipated. (5 pts)

Added by Stephen S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ivan Kochetkov

01/21/2023

Step 1

Given: Length (l) = 1000 ft = 304.8 m Diameter (d) = 0.8 in = 0.02 m Conductivity (σ) = 3.82 x 10^7 mho/m^2 Resistance (R) = ρ * (l / A) where ρ is the resistivity, l is the length, and A is the cross-sectional area. Cross-sectional area (A) = π * (d/2)^2 A = π Show more…

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3. An aluminum conductor is 1000 ft. long and has a circular cross-section with a diameter of 0.8 in2. If there is a dc voltage of 1.2 V between the ends, find: (σ = 3.82 x 107 mho/m2) a. the current density (5 pts) b. the current (5 pts) c. the power dissipated. (5 pts)