00:01
First ones let abcd is a kite which is a convex portrait nail whose four sides consist of two pair of congruent adjacent sides.
00:11
Therefore, ab equal to ad and bc equal to cd.
00:19
Now we draw two diagonals ac and bd which intersect at point o.
00:27
From the triangle abc and acd we have ac is common and bc equal to cd and ab equal to ad.
01:00
Therefore, triangle abc congruent to triangle acd.
01:12
So which means the angle acb equal to angle acd.
01:18
Consider this is equation 1 and angle abc equal to angle adc.
01:26
Consider this is equation 2 and angle bac equal to angle bac.
01:34
Consider this is equation 3.
01:36
Now for the triangle aob and triangle aod here oa is common and ab equal to ad and angle bac equal to angle bac.
02:14
Therefore, triangle aob congruent to triangle aod...