3. find the Laplace transformation F(s) (1). f(t) = {-1 0 < t < 1, 1 1 < t < 2, where T = 2. (2). f(t) = {t 0 < t < ?, 0 ? < t < 2?, where T = 2?. (3). f(t) = e^t (0 < t < 2), where T = 2. (4). f(t) = {e^t 0 < t < 2, 0 2 < t < 4, where T = 4.
Added by Donald M.
Close
Step 1
The Laplace transform is: F(s) = ∫_0^1 e^(-st) (-1) dt = -[e^(-s) - 1]/s 2) For 1 < t < 2, f(t) = 1. The Laplace transform is: Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 56 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
1) The Laplace transform of e^3t 2) The Laplace transform of sin(2t) 3) The Laplace transform of te^t 4) Let f(t) = 1 if 0 <= t <= 3, t - 2 if t > 3 5) The Laplace transform of e^t * t^3 + sin(3t)
Sri K.
4. Find the Laplace transform of the following functions: (a) 5 - e^{2t} + 6t^{2} (b) t^{3}e^{5t} - e^{t} cos sqrt{7}t (c) f(t) = { e^{2t}, 0 < t < 3; 1, t > 3}
Try this one! Find the Laplace transform of the following functions: f(t) = (t + 2)^2 * e^t f(t) = ~e^-3t * sin(4t) + 3 f(t) = 2 * e^3t * sin(2t) - 3 * e^3t * cos(2t) f(t) = (1 + t * e^-t)^2 f(t) = (1 - sin(4t))^2 * e^-5t s^2 - s + 1 If [f(t)], find V[e^2tf(3t)]. (2s + 1)^2 * (s - 1) (2t, 0 < t < 1; t > 1), find % [f(t)] (t) If f(t) If f(t) (5 * sin(3(t - %)), t >), find F[f(t)] (t <)
Shaiju T.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD