00:01
We want to find the maximum and minimum values of f subject to these constraints.
00:06
So we have an objective function with two lagrange multipliers.
00:10
It looks like this.
00:17
Let's take all the derivatives and set them equal to zero and number them.
00:52
So equation one tells us this.
00:55
Equation three.
01:02
Equation two.
01:08
There's a subtle point in how i got equation three.
01:11
We'll come back to it.
01:12
I divided out z.
01:19
And then equation four tells us y gives us x and y.
01:30
And so equation five tells us z squared tells us z.
01:42
And then we can calculate our x squared plus y squared minus z squared.
01:49
It's out to be minus 1 3rd.
02:07
Okay.
02:07
So that's the minimum.
02:10
So the point about equation three is i divided out a z...