00:01
Hello everyone, in this question we are given with p of x, q of x, r of x and s of x.
00:13
The predicates are in domain z.
00:17
Now for each predicate we have to determine the truth set.
00:22
So we are given with f of x is equal to x square plus 2x minus 15 equal to 0.
00:30
So this is the equation we are given.
00:34
So this can be written as x plus 3, so x minus 3 into x plus 5 equal to 0.
00:47
So therefore the x values will be 3 comma minus 5.
00:51
So here the values of p of x such that x belongs to 3 comma minus 5 is in the domain z.
01:07
So this belongs to z.
01:10
So therefore we can say the statement is it is true.
01:17
Now let us move on to the next.
01:23
So we are given with q of x such that x is odd.
01:29
So x is odd means we can write this as x will be equal to plus or minus 1, plus or minus 3, plus or minus 5, etc., etc.
01:45
It keeps going.
01:46
So therefore this values that is q of x such that x is odd.
01:54
So this values belongs to z...