Question

3. Lucy wrote \( \int x(x^2 + 1) dx = (\frac{1}{2}x^2)(\frac{1}{3}x^3 + x) + c \). She earned zero points because she didn't show any work! But is Lucy correct? Explain why or why not by showing your work in evaluating the integral.

Name: 3. Lucy wrote ∫ x(x^2 + 1) dx = ((1)/(2)x^2)((1)/(3)x^3 + x) + c. She earned zero points because she didn't show any work! But is Lucy correct? Explain why or why not by showing your work in evaluating the integral.
Uploaded: 2021-10-01T17:30:16-08:00
Duration: 1 min 2 s
Channel: Rukhmani Jain
Description: 3. Lucy wrote ∫ x(x^2 + 1) dx = ((1)/(2)x^2)((1)/(3)x^3 + x) + c. She earned zero points because she didn't show any work! But is Lucy correct? Explain why or why not by showing your work in evaluating the integral.

          3. Lucy wrote \( \int x(x^2 + 1) dx = (\frac{1}{2}x^2)(\frac{1}{3}x^3 + x) + c \). She earned zero points because she didn't show any work! But is Lucy correct? Explain why or why not by showing your work in evaluating the integral.

3. Lucy wrote ∫ x(x^2 + 1) dx = ((1)/(2)x^2)((1)/(3)x^3 + x) + c. She earned zero points because she didn't show any work! But is Lucy correct? Explain why or why not by showing your work in evaluating the integral.

Added by Helen B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Rukhmani Jain

10/01/2021

Step 1

∫(x(x^2 + 1)) dx = ∫(x^3 + x) dx Show more…

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3. Lucy wrote ∫(x(x^2 + 1)) dx = (x^2)(x^3 + x) + c. She earned zero points because she didn't show any work! But is Lucy correct? Explain why or why not by showing your work in evaluating the integral.