In this problem, we construct several solutions to a single IVP. This would contradict the existence and uniqueness theorem if the hypotheses of that theorem were satisfied (luckily, they aren't):
Consider the initial value problem:
y(t) = y(0)
There is a constant solution to this IVP. Find it.
For the same IVP as part (a), is there a continuously differentiable solution at t = 0? If t > 0, y(t) = t; if t < 0, y(t) = 0. Find the non-zero constant for which this is a solution.
Consider the initial value problem:
y(t) = Vyy(0)
There is a constant solution to this IVP. Find it.
For the same IVP as part (c), is there a continuously differentiable solution at t = 0? If t > 0, y(t) = t^2; if t < 0, y(t) = 0. Find the non-zero constant for which this is a solution.